C program to search for a given number in an array

Below is a C program which allows an user to enter a maximum of 10 numbers. It also allows an user to search whether a given number is available or not. If the given number is available, the program displays the index within the array at which the number is found.

/*Program to search for a given number in an array*/
#include<stdio.h>
#include<conio.h>
void main()
{
    int arr[10],n,i,num,flag=0;
    printf("How many numbers you want to enter:");
    scanf("%d",&num);
    if(num>10||num<1)
    {
        printf("Size cannot be greater than 10 and less than 1.Try again...!");
    }
    else
    {
        /*Reading the array elements*/
        printf("Enter the array elements:\n");
        for(i=0;i<num;i++)
        {
            scanf("%d",&arr[i]);
        }
        /*Reading the number to search in the array*/
        printf("Enter the number you want to search:");
        scanf("%d",&n);
        /*Code to check if the number is available in the array or not*/
        for(i=0;i<num;i++)
        {
            if(arr[i]==n)
            {
                printf("%d is found at index %d\n",n,i);
                flag = 1;
            }
        }
        if(flag==0)
        printf("Given number is not available in the array.");
    }
    getch();
}


Sample input and output:

How many numbers you want to enter:5
Enter the array elements:
1 2 3 4 5
Enter the number you want to search:3
3 is found at index 2